2012 AMC 8 第 9 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

Fort Worth Zoo 有一些两条腿的鸟和一些四条腿的哺乳动物。Margie 某次参观动物园时数到二百个头和五百二十二条腿。Margie 数到的动物中有多少只是两条腿的鸟?

The Fort Worth Zoo has a number of two-legged birds and a number of four-legged mammals. On one visit to the zoo, Margie counted 200 heads and 522 legs. How many of the animals that Margie counted were two-legged birds?

6161

122122

139139

150150

161161

答案:C
知识点:方程组
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文字解答:

ff44 条腿动物的数量,tt22 条腿动物的数量。

数腿得到 2t+4f=5222t+4f = 522,数头得到 t+f=200t + f = 200。将第二式乘以四,得 4t+4f=8004t+4f = 800。减去第一式,得到 2t=278    t=1392t = 278 \implies t = 139。因此有 139139 只两条腿的鸟。

所以正确答案是 C

Let ff be the number of animals with 44 legs and let tt be the number of animals with 22 legs.

Counting the number of legs yields 2t+4f=5222t+4f = 522 and counting the number of heads yields t+f=200.t + f = 200. This means 4t+4f=800,4t+4f = 800, and subtracting the first equation from the second yields 2t=278    t=139.2t = 278 \implies t = 139. This means there are 139139 two-legged birds.

Thus, the answer is C .

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