2012 AMC 8 第 9 题

先试着解答 2012 AMC 8 第 9 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2012 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

Fort Worth Zoo 有一些两条腿的鸟和一些四条腿的哺乳动物。Margie 某次参观动物园时数到 200200 个头和 522522 条腿。Margie 数到的动物中有多少是两条腿的鸟?
The Fort Worth Zoo has a number of two-legged birds and a number of four-legged mammals. On one visit to the zoo, Margie counted 200200 heads and 522522 legs. How many of the animals that Margie counted were two-legged birds?
6161
122122
139139
150150
161161
答案:C
知识点:方程组
小提示:
先假设每只动物都有两条腿。
Start by giving every animal two legs.
大提示:
多出来的腿决定四条腿哺乳动物的数量。
The extra legs determine the number of four-legged mammals.
视频讲解:
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文字解答:
设 ff 为 44 条腿动物的数量,tt 为 22 条腿动物的数量。
数腿得到 2t+4f=5222t+4f = 522,数头得到 t+f=200t + f = 200。将第二式乘以四,得 4t+4f=8004t+4f = 800。减去第一式,得到 2t=278  ⟹  t=1392t = 278 \implies t = 139。因此有 139139 只两条腿的鸟。
所以正确答案是 C。
Let ff be the number of animals with 44 legs and let tt be the number of animals with 22 legs.
Counting the number of legs yields 2t+4f=5222t+4f = 522 and counting the number of heads yields t+f=200.t + f = 200. This means 4t+4f=800,4t+4f = 800, and subtracting the first equation from the second yields 2t=278  ⟹  t=139.2t = 278 \implies t = 139. This means there are 139139 two-legged birds.
Thus, the answer is C .
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