2012 AMC 8 第 23 题

先试着解答 2012 AMC 8 第 23 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2012 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

一个等边三角形和一个正六边形周长相等。如果三角形面积为 44,那么六边形面积是多少?
An equilateral triangle and a regular hexagon have equal perimeters. If the triangle’s area is 44, what is the area of the hexagon?
44
55
66
434\sqrt3
636\sqrt3
答案:C
知识点:等边三角形正多边形面积比
小提示:
周长相等使六边形边长为三角形边长的一半。
Equal perimeters make the hexagon side half the triangle side.
大提示:
正六边形由六个全等等边三角形组成。
A regular hexagon is made from six congruent equilateral triangles.
视频讲解:
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文字解答:
设三角形边长为 ss。其周长为 3s3s,所以六边形边长为 3s6=s2\frac{3s}{6} = \frac s2。
如图,正六边形可分成 66 个边长为 s2\dfrac{s}{2} 的等边三角形。每个小三角形是原三角形按比例 12\dfrac{1}{2} 缩小得到的,所以面积缩小为 (12)2=14(\dfrac{1}{2})^2 = \dfrac{1}{4} 。因此每个小三角形面积为 4⋅14=14 \cdot \dfrac{1}{4} = 1。共有 66 个,所以六边形面积为 6⋅1=66\cdot 1 = 6。
所以正确答案是 C。
Let the side length of the triangle be s.s. This means the perimeter is 3s.3s. Therefore, the side length for the hexagon is 3s6=s2. \frac{3s}{6} = \frac s2.
A hexagon can be made of 66 equilateral triangles with side length s2 \dfrac{s}{2} as shown above. Each triangle is the original triangle scaled down by 12,\dfrac{1}{2}, so the area is scaled down by (12)2=14. (\dfrac{1}{2})^2 = \dfrac{1}{4} . Therefore, the area of each of these triangles is 4⋅14=1.4 \cdot \dfrac{1}{4} = 1. Since there are 66 of them, the area is 6⋅1=6.6\cdot 1 = 6.
Thus, the answer is C .
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