2007 AMC 8 第 7 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

一个房间里 55 个人的平均年龄是 3030 岁。一名 1818 岁的人离开房间。剩下四个人的平均年龄是多少?

The average age of 55 people in a room is 3030 years. An 1818-year-old person leaves the room. What is the average age of the four remaining people?

2525

2626

2929

3333

3636

答案:D
知识点:平均数
难度评级:900
解答:

起初,房间里所有人的总年龄为 530=1505 \cdot 30 = 150 岁。

这个人离开后,总年龄为 15018=132150 - 18 = 132。剩下 44 人,平均年龄为 1324=33\dfrac{132}{4} = 33

所以正确答案是 D

Initially, the total age of everyone in the room is 530=1505 \cdot 30 = 150 years.

After the person leaves, the total age is 15018=132.150 - 18 = 132. With 44 people remaining, the average age becomes 1324=33.\dfrac{132}{4} = 33.

Thus, D is the correct answer.

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