2005 AMC 8 第 17 题

先试着解答 2005 AMC 8 第 17 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2005 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

17.

图中显示了一支越野队训练跑的结果。哪位学生的平均速度最大?
The results of a cross-country team’s training run are graphed below. Which student has the greatest average speed?
Angela\text{Angela}
Briana\text{Briana}
Carla\text{Carla}
Debra\text{Debra}
Evelyn\text{Evelyn}
答案:E
知识点:数据与图表解读斜率
小提示:
平均速度等于距离除以时间
Average speed is distance divided by time.
大提示:
在图上,比较从原点到各点的斜率
On the graph, compare slopes from the origin.
解答:
平均速度是距离除以时间,也就是从原点到该点连线的斜率。
Evelyn 的斜率最大,因此她的平均速度最大。
所以正确答案是 E。
Average speed is distance over time, which is given by the slope of the line through the point and the origin.
Evelyn has the steepest slope, telling us that she had the greatest average speed.
Thus, E is the correct answer.
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