2004 AMC 8 第 9 题

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9.

一个列表中五个数的平均数是 5454。前两个数的平均数是 4848。后三个数的平均数是多少?

The average of the five numbers in a list is 54.54. The average of the first two numbers is 48.48. What is the average of the last three numbers?

5555

5656

5757

5858

5959

答案:D
知识点:平均数
难度评级:1020
解答:

55 个数的总和是 545=27054 \cdot 5 = 270。前 22 个数的总和是 482=9648 \cdot 2 = 96

33 个数的总和是 27096=174270 - 96 = 174,所以平均数是 174÷3=58174 \div 3 = 58

所以正确答案是 D

The sum of all 55 numbers is 545=270.54 \cdot 5 = 270. The sum of the first 22 numbers is 482=96.48 \cdot 2 = 96.

The sum of the last 33 numbers is 27096=174.270 - 96 = 174. The average is therefore 174÷3=58.174 \div 3 = 58.

Thus, D is the correct answer.

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