2001 AMC 8 第 6 题

先试着解答 2001 AMC 8 第 6 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2001 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

六棵树沿着一条直路的一侧等间距排列。第一棵树到第四棵树的距离是 6060 英尺。第一棵树到最后一棵树之间的距离是多少英尺?
Six trees are equally spaced along one side of a straight road. The distance from the first tree to the fourth is 6060 feet. What is the distance in feet between the first and last trees?
9090
100100
105105
120120
140140
答案:B
知识点:植树问题比与比例
小提示:
第一棵到第四棵之间有三个相等间隔
The first to fourth trees contain three equal gaps
大提示:
第一棵到最后一棵之间有五个相等间隔
The first to last trees contain five equal gaps
解答:
第一棵和第四棵之间有 33 个间隔,因此每个间隔长 60÷3=2060 \div 3 = 20 英尺。
第一棵和最后一棵之间有 55 个间隔,所以它们相距 5⋅20=1005 \cdot 20 = 100 英尺。
所以正确答案是 B。
There are 33 gaps between the first and fourth trees, which means that one gap is 60÷3=2060 \div 3 = 20 feet long.
There are 55 gaps between the first and last trees. This means that they are 5⋅20=1005 \cdot 20 = 100 feet apart.
Thus, B is the correct answer.
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