2000 AMC 8 第 7 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

从集合 {8,6,4,0,3,5,7}\{-8,-6,-4,0,3,5,7\} 中选三个不同的数,它们的乘积最小可能是多少?

What is the minimum possible product of three different numbers of the set {8,6,4,0,3,5,7}?\{-8,-6,-4,0,3,5,7\}?

336-336

280-280

210-210

192-192

00

答案:B
知识点:最优化分类讨论
难度评级:940
解答:

要用三个数得到负乘积,可以选一个负数和两个正数,也可以选三个负数。

只有 22 个可行选择需要比较: 864=192 -8 \cdot -6 \cdot -4 = -192 857=280. -8 \cdot 5 \cdot 7 = -280. 后者显然更小。

所以正确答案是 B

To get a negative product using three numbers, you can either multiply one negative number and two positives, or three negatives.

The only 22 viable options are 864=192 -8 \cdot -6 \cdot -4 = -192 and 857=280. -8 \cdot 5 \cdot 7 = -280. The latter is clearly the lesser value.

Thus, B is the correct answer.

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