1999 AMC 8 第 9 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

如图,三个花坛互相重叠。花坛 A 有 500500 株植物,花坛 B 有 450450 株植物,花坛 C 有 350350 株植物。A 和 B 共有 5050 株植物,A 和 C 共有 100100 株植物。植物总数是

Three flower beds overlap as shown. Bed A has 500500 plants, bed B has 450450 plants, and bed C has 350350 plants. Beds A and B share 5050 plants, while beds A and C share 100.100. The total number of plants is

850850

10001000

11501150

13001300

14501450

答案:C
知识点:容斥原理韦恩图
难度评级:1020
解答:

50+100=15050 + 100 = 150 株植物在两个花坛中,且没有植物同时在三个花坛中。

所以植物总数为 减去是为了去掉被计算两次的植物。 500+450+350150=1150. 500 + 450 + 350 - 150 = 1150.

所以正确答案是 C

Note there are 50+100=15050 + 100 = 150 plants that are in two beds and there are no plants in all three beds.

The total number of plants is then 500+450+350150=1150. 500 + 450 + 350 - 150 = 1150. We subtract to get rid of the plants that we counted twice.

Thus, C is the correct answer.

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