Question

$10$ 点整时，钟表两根指针形成的较小角的度数是多少？

What is the degree measure of the smaller angle formed by the hands of a clock at $10$ o'clock?

$30$

$45$

$60$

$75$

$90$

知识点：时钟

$10$ 点整时，时针指向 $10$ ，分针指向 $12$ 。

两根指针相隔整个圆的 $\frac{1}{6}$ 。所以角度为 $360^{\circ} \cdot \dfrac{1}{6} = 60^{\circ}.$

所以正确答案是 C。

At $10$ o'clock, we have that the hour hand is at $10$ and the minute hand is at $12.$

This means that the hands are a $\frac{1}{6}$ of the entire circle apart. This is equal to $360^{\circ} \cdot \dfrac{1}{6} = 60^{\circ}.$

Thus, C is the correct answer.