1998 AMC 8 第 1 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

x=7x = 7 时,下列哪一个最小?

For x=7,x = 7, which of the following is the smallest?

6x\dfrac{6}{x}

6x+1\dfrac{6}{x+1}

6x1\dfrac{6}{x-1}

x6\dfrac{x}{6}

x+16\dfrac{x+1}{6}

答案:B
知识点:换元法分数
难度评级:450
小提示:

先代入 x=7x = 7

Substitute x=7x = 7 first.

大提示:

分子相同时,比较分母大小。

With equal numerators, compare denominators.

解答:

代入 x=7x = 7,五个选项的值依次为 67\dfrac{6}{7}68\dfrac{6}{8}1176\dfrac{7}{6}43\dfrac{4}{3}

只有前两个值小于 11。这两个分数的分子相同,所以分母较大的分数较小。因此正确答案是 B

Substituting x=7x = 7 gives the five values 67,\dfrac{6}{7}, 68,\dfrac{6}{8}, 1,1, 76,\dfrac{7}{6}, and 43.\dfrac{4}{3}.

The first two are the only values less than 1.1. Because they have the same numerator, the fraction with the larger denominator is smaller. Thus, the correct answer is B .

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