Question

下表给出 Annville 和 Cleona 两所小学各年级学生所占百分比。K、 $1, 2, 3, 4, 5, 6$ 年级的百分比分别为：Annville： $16\%$ 、 $15\%$ 、 $15\%$ 、 $14\%$ 、 $13\%$ 、 $16\%$ 、 $11\%$ ；Cleona： $12\%$ 、 $15\%$ 、 $14\%$ 、 $13\%$ 、 $15\%$ 、 $14\%$ 、 $17\%$ 。

Annville 有 $100$ 名学生，Cleona 有 $200$ 名学生。两所学校合计，有百分之几的学生在 $6$ 年级？

The table below gives the percent of students in each grade at Annville and Cleona elementary schools. The percentages for grades K, $1, 2, 3, 4, 5, 6$ are: Annville: $16\%,$ $15\%,$ $15\%,$ $14\%,$ $13\%,$ $16\%,$ $11\%;$ Cleona: $12\%,$ $15\%,$ $14\%,$ $13\%,$ $15\%,$ $14\%,$ $17\%.$

Annville has $100$ students and Cleona has $200$ students. In the two schools combined, what percent of the students are in grade $6?$

$12\%$

$13\%$

$14\%$

$15\%$

$28\%$

答案：D

知识点：百分数平均数

难度评级：980

解答：

Annville 的六年级人数为 $11\%$ 乘以 $100 = 11$ 人；Cleona 的六年级人数为 $17\%$ 乘以 $200 = 34$ 人。

合计为 $11 + 34 = 45$ 人，占总人数 $300$ 的 $\dfrac{45}{300} = 15\%$ 。

所以正确答案是 D。

Annville has $11\%$ of $100 = 11$ sixth graders, and Cleona has $17\%$ of $200 = 34$ sixth graders.

Combined, that is $11 + 34 = 45$ out of $300$ students, which is $\dfrac{45}{300} = 15\%.$

Thus, the correct answer is D .

1995 AMC 8 第 17 题

答案：D

难度评级：980

解答：

其他年份的第 17 题