2026 AMC 8 Problem 6

Attempt Problem 6 of the 2026 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2026 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Peter lives near a rectangular field that is filled with blackberry bushes. The field is 1010 meters long and 88 meters wide, and Peter can reach any blackberries that are within 11 meter of an edge of the field. The portion of the field he can reach is shaded in the figure below. What fraction of the area of the field can Peter reach?
16\dfrac{1}{6}
14\dfrac{1}{4}
13\dfrac{1}{3}
38\dfrac{3}{8}
25\dfrac{2}{5}
Answer: E
Concepts:areafraction
Small hint:
Find the unreachable inner rectangle
Big hint:
Reachable area = field area - inner area
Video solution:
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Written solution:
The whole field has area 10⋅8=8010\cdot8=80. The unreachable inner rectangle is 88 meters by 66 meters, with area 4848. Thus the reachable area is 80−48=3280-48=32, and the fraction is 3280=25\frac{32}{80}=\frac{2}{5}.
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