2026 AMC 8 Problem 14

Attempt Problem 14 of the 2026 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2026 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

Jami picked three equally spaced integer numbers on the number line. The sum of the first and the second numbers is 40,40, while the sum of the second and third numbers is 60.60. What is the sum of all three numbers?
7070
7575
8080
8585
9090
Answer: B
Concepts:arithmetic sequencesystem of equations
Small hint:
Let the three numbers be a−d,a,a+da-d, a, a+d
Big hint:
The two given sums differ by 2020, so 2d=202d=20
Video solution:
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Written solution:
Let the three equally spaced numbers be a−da-d, aa, and a+da+d. The given sums are 2a−d=402a-d=40 and 2a+d=602a+d=60. Adding gives 4a=1004a=100, so a=25a=25. The total of the three numbers is 3a=753a=75.
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