2016 AMC 8 Problem 13

Attempt Problem 13 of the 2016 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

Two different numbers are randomly selected from the set {−2,−1,0,3,4,5}\{ - 2, -1, 0, 3, 4, 5\} and multiplied together. What is the probability that the product is 0?0?
16 \dfrac{1}{6}
15 \dfrac{1}{5}
14 \dfrac{1}{4}
13 \dfrac{1}{3}
12 \dfrac{1}{2}
Answer: D
Concepts:basic probabilitycounting pairs
Small hint:
A product is 00 exactly when one of the selected numbers is 00.
Big hint:
Count selections containing 00 out of all ways to choose two different numbers.
Video solution:
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Written solution:
There are (62)=15\binom62=15 ways to select two different numbers. A product is 00 exactly when one selected number is 00, and there are 55 choices for the other number. Thus the probability is 515=13.\dfrac5{15}=\dfrac13.
Thus, D is the correct answer.
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