2015 AMC 8 Problem 10
Attempt Problem 10 of the 2015 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
10.
How many integers between and have four distinct digits?
Answer: B
Small hint:
Choose the thousands digit first.
Big hint:
After that, each later digit must avoid all previously chosen digits.
Video solution:
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Written solution:
First, there are digits to choose for the thousands digit since can’t be chosen.
Then, after that, there are ways to choose the hundreds digit, ways to choose the tens digit, and ways to choose the ones digit. Therefore, we get ways to choose such an integer.
Thus, the correct answer is B .
Problem 10 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
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- 1996 AMC 8
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- 1998 AMC 8
- 1999 AMC 8
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