2014 AMC 8 Problem 6

Attempt Problem 6 of the 2014 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Six rectangles each with a common base width of 22 have lengths of 1,1, 4,4, 9,9, 16,16, 25,25, and 36.36. What is the sum of the areas of the six rectangles?
91 91
93 93
162 162
182 182
202 202
Answer: D
Concepts:rectanglearea
Small hint:
Each rectangle has area 22 times its listed length.
Big hint:
Add the lengths first, then multiply by 22.
Solution:
To find the area of each rectangle we multiply 22 by their respective lengths. This means that we can factor out the 22 and we are left with the sum of the lengths. Adding together the lengths, we get 91.91.
Therefore, the sum of the areas is 2⋅91=182.2 \cdot 91 = 182.
Thus, D is the correct answer.
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