2010 AMC 8 Problem 14

Attempt Problem 14 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

What is the sum of the prime factors of 2010?2010?
 67 \ 67
 75 \ 75
 77 \ 77
 201 \ 201
 210 \ 210
Answer: C
Concepts:prime factorization
Small hint:
After removing 22, 55, and 33, the remaining factor is prime.
Big hint:
Factor 20102010 using divisibility by 1010 and by 33.
Solution:
First, the primes 2,2, 55 are factors of 20102010 since it is a multiple of 10.10. Dividing 20102010 by 1010 is 201.201. Then, 33 is a factor of 201201 since the digit sum of 201201 is a multiple of 3.3. Dividing this by 33 yields the prime number 67.67. This means the prime factors are 2,2, 3,3, 5,5, 67,67, which makes their sum 77.77.
Thus, the correct answer is C .
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