2010 AMC 8 Problem 12

Attempt Problem 12 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Of the 500500 balls in a large bag, 80%80\% are red and the rest are blue. How many of the red balls must be removed so that 75%75\% of the remaining balls are red?
 25 \ 25
 50 \ 50
 75 \ 75
 100 \ 100
 150 \ 150
Answer: D
Concepts:percentage
Small hint:
If red balls are 75%75\%, then blue balls are 25%25\% of the remaining bag.
Big hint:
The number of blue balls stays fixed.
Solution:
If rr is the number of red balls, then r=0.8⋅500=400.r = 0.8\cdot500 = 400. Therefore, if bb is the number of blue balls, then b=500−400=100.b = 500-400 = 100.
If there are 75%75\% red balls after removing balls, then there are 25%25\% blue balls. This means the total number of balls is 1000.25=400.\dfrac{100}{0.25} = 400. This means the total number of balls decreased by 500−400=100.500-400 = 100.
Thus, the answer is D .
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