2010 AMC 8 Problem 10

Attempt Problem 10 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Six pepperoni circles will exactly fit across the diameter of a 1212-inch pizza when placed as shown. If a total of 2424 circles of pepperoni are placed on this pizza without overlap, what fraction of the pizza is covered by pepperoni?
 12 \ \dfrac 12
 23 \ \dfrac 23
 34 \ \dfrac 34
 56 \ \dfrac 56
 78 \ \dfrac 78
Answer: B
Concepts:circle areaarea ratiopower scaling of length, area, and volume
Small hint:
Area scales with the square of the diameter, then multiply by 2424 pepperoni circles.
Big hint:
Six small diameters equal the pizza diameter.
Solution:
Each circle has 16\dfrac{1}{6} the diameter of the large circle, so it has (16)2=136(\frac 16)^2 = \frac 1{36} of the total area.
Since there are 2424 pepperoni, they take up 24⋅136=2324 \cdot \dfrac 1{36} = \frac 23 of the area.
Therefore, the answer is B .
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