2010 AMC 8 Problem 10

Attempt Problem 10 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

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10.

Six pepperoni circles will exactly fit across the diameter of a 1212-inch pizza when placed as shown. If a total of 2424 circles of pepperoni are placed on this pizza without overlap, what fraction of the pizza is covered by pepperoni?

 12 \ \dfrac 12

 23 \ \dfrac 23

 34 \ \dfrac 34

 56 \ \dfrac 56

 78 \ \dfrac 78

Answer: B
Concepts:circle areaarea ratiopower scaling of length, area, and volume
Difficulty rating: 1030
Solution:

Each circle has 16\dfrac{1}{6} the diameter of the large circle, so it has (16)2=136(\frac 16)^2 = \frac 1{36} of the total area.

Since there are 2424 pepperoni, they take up 24136=2324 \cdot \dfrac 1{36} = \frac 23 of the area.

Therefore, the answer is B .

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