2009 AMC 8 Problem 6

Attempt Problem 6 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Steve’s empty swimming pool will hold 24,00024{,}000 gallons of water when full. It will be filled by 44 hoses, each of which supplies 2.52.5 gallons of water per minute. How many hours will it take to fill Steve’s pool?
4040
4242
4444
4646
4848
Answer: A
Concepts:rateunit conversion
Small hint:
First find the combined filling rate of the four hoses.
Big hint:
Convert minutes to hours after finding the total number of minutes.
Solution:
The 44 hoses together fill the pool with 2.5⋅4=102.5 \cdot 4 = 10 gallons of water per minute.
To fill 24,00024{,}000 gallons, it will take the hoses 24,000÷10=2,40024{,}000 \div 10 = 2{,}400 minutes to fill the pool.
2,4002{,}400 minutes is the same as 2,400÷60=402{,}400 \div 60 = 40 hours.
Thus, A is the correct answer.
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