2009 AMC 8 Problem 17

Attempt Problem 17 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

The positive integers xx and yy are the two smallest positive integers for which the product of 360360 and xx is a square and the product of 360360 and yy is a cube. What is the sum of xx and y?y?
8080
8585
115115
165165
610610
Answer: B
Concepts:prime factorizationperfect squareperfect power
Small hint:
Factor 360360 into primes.
Big hint:
Make exponents even for a square and multiples of 33 for a cube.
Solution:
For a number to be a perfect square, every exponent in the prime factorization must be even. For it to be a cube, the exponents must be divisible by 3.3.
We can factor 360360 to get 360=23⋅32⋅5. 360 = 2^3 \cdot 3^2 \cdot 5. For 360x360x to be a perfect square and xx to be minimized, xx must have one factor of 22 and one factor of 5.5. Therefore, we can let x=10.x = 10.
For 360y360y to be a cube, yy must have one factor of 33 and two factors of 5.5. Therefore, we can let y=75,y = 75, suggesting x+y=85.x + y = 85.
Thus, B is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.