2009 AMC 8 Problem 13

Attempt Problem 13 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

A three-digit integer contains one of each of the digits 1,1, 3,3, and 5.5. What is the probability that the integer is divisible by 5?5?
16\dfrac{1}{6}
13\dfrac{1}{3}
12\dfrac{1}{2}
23\dfrac{2}{3}
56\dfrac{5}{6}
Answer: B
Concepts:basic probabilitydivisibility
Small hint:
A number is divisible by 55 exactly when its last digit is 00 or 5.5.
Big hint:
With digits 1,1, 3,3, and 5,5, each digit is equally likely to be last.
Solution:
The number is equally likely to end in 1,1, 3,3, or 5.5.
It is divisible by 55 only if the last digit is 5,5, which happens with probability 13.\dfrac{1}{3}.
Thus, B is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.