2008 AMC 8 Problem 12

Attempt Problem 12 of the 2008 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

A ball is dropped from a height of 33 meters. On its first bounce it rises to a height of 22 meters. It keeps falling and bouncing to 23\frac{2}{3} of the height it reached in the previous bounce. On which bounce will it not rise to a height of 0.50.5 meters?
 3 \ 3
 4 \ 4
 5 \ 5
 6 \ 6
 7 \ 7
Answer: C
Concepts:geometric sequence
Small hint:
List the bounce heights by multiplying by 23\frac{2}{3} each time.
Big hint:
Compare the fourth and fifth bounce heights with 12\frac{1}{2}.
Solution:
The first bounce rises to 22 meters. Each later bounce is 23\dfrac{2}{3} of the previous bounce.
The fourth bounce rises to 2(23)3=16272\left(\dfrac{2}{3}\right)^3=\dfrac{16}{27}, which is greater than 12\dfrac{1}{2}.
The fifth bounce rises to 2(23)4=32812\left(\dfrac{2}{3}\right)^4=\dfrac{32}{81}, which is less than 12\dfrac{1}{2}.
Thus, C is the correct answer.
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