2008 AMC 8 Problem 10
Attempt Problem 10 of the 2008 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
10.
The average age of the people in Room A is The average age of the people in Room B is If the two groups are combined, what is the average age of all the people?
Answer: D
Small hint:
Convert each room average into a total age.
Big hint:
The combined average is the combined total age divided by all people.
Solution:
The sum of the ages in Room A is
The sum of the ages in Room B is
The total sum is
The average is therefore
Thus, the answer is D .
Problem 10 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
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- 1989 AMC 8
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- 1991 AMC 8
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