2007 AMC 8 Problem 10

Attempt Problem 10 of the 2007 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

For any positive integer n,n, define n\boxed{n} to be the sum of the positive factors of n.n. For example, 6=1+2+3+6=12. \boxed{6} = 1 + 2 + 3 + 6 = 12. Find 11.\boxed{\boxed{11}}.
1313
2020
2424
2828
3030
Answer: D
Concepts:sum of factorscustom operation
Small hint:
Apply the boxed operation once to 1111 first.
Big hint:
Then apply the same sum-of-factors operation to the result.
Solution:
First, we find that 11=1+11=12 \boxed{11} = 1 + 11 = 12 since 1111 is prime. Then we need to find 12.\boxed{12}. The factors of 1212 are 1,2,3,4,6,12. 1, 2, 3, 4, 6, 12. Adding these yields 12=28.\boxed{12} = 28.
Thus, D is the correct answer.
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