2006 AMC 8 Problem 9

Attempt Problem 9 of the 2006 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

What is the product of 32×43×54×⋯×20062005?\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times\cdots\times\dfrac{2006}{2005}?
11
10021002
10031003
20052005
20062006
Answer: C
Concepts:telescoping
Small hint:
Most adjacent numerators and denominators cancel.
Big hint:
After cancellation, only the first denominator and the last numerator remain.
Solution:
Note that the numerator of every fraction cancels with the denominator of the following fraction. This leaves two numbers: 20062=1003. \dfrac{2006}{2} = 1003.
Thus, C is the correct answer.
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