2003 AMC 8 Problem 12

Attempt Problem 12 of the 2003 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

When a fair six-sided die is tossed on a table top, the bottom face cannot be seen. What is the probability that the product of the numbers on the five faces that can be seen is divisible by 6?6?
13\frac{1}{3}
12\frac{1}{2}
23\frac{2}{3}
56\frac{5}{6}
11
Answer: E
Concepts:basic probabilitydivisibility
Small hint:
Check the only case where the face numbered 66 is hidden.
Big hint:
If 66 is hidden, the visible faces still include 22 and 3.3.
Solution:
If the face numbered 66 is visible, then the visible product is divisible by 6.6.
If the face numbered 66 is on the bottom, then the visible faces include both 22 and 3,3, so their product is still divisible by 6.6.
Every possible toss works, so the probability is 1.1.
Thus, E is the correct answer.
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