2002 AMC 8 Problem 3
Attempt Problem 3 of the 2002 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
3.
What is the smallest possible average of four distinct positive even integers?
Answer: C
Small hint:
To make the average as small as possible, choose the smallest possible integers.
Big hint:
Use the four smallest distinct positive even integers.
Solution:
To get the smallest possible average, we want to use the smallest positive even integers.
This can be achieved as follows:
Thus, C is the correct answer.
Problem 3 in other years
- 1985 AMC 8
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