2001 AMC 8 Problem 6

Attempt Problem 6 of the 2001 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Six trees are equally spaced along one side of a straight road. The distance from the first tree to the fourth is 6060 feet. What is the distance in feet between the first and last trees?
9090
100100
105105
120120
140140
Answer: B
Concepts:fencepost countingratio and proportion
Small hint:
The first to fourth trees contain three equal gaps
Big hint:
The first to last trees contain five equal gaps
Solution:
There are 33 gaps between the first and fourth trees, which means that one gap is 60÷3=2060 \div 3 = 20 feet long.
There are 55 gaps between the first and last trees. This means that they are 5⋅20=1005 \cdot 20 = 100 feet apart.
Thus, B is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.