2000 AMC 8 Problem 14

Attempt Problem 14 of the 2000 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

What is the units digit of 1919+9999?19^{19} + 99^{99}?
00
11
22
88
99
Answer: D
Concepts:units digitmodular exponentiation
Small hint:
Only the units digit matters
Big hint:
Odd powers of a number ending in 99 end in 99
Solution:
Note that the units digit of a power depends only upon the units digit of the base.
Experimenting, we get that 99 to an even power ends with a 11 and to an odd power ends with a 9.9.
Therefore, 191919^{19} ends with a 99 and 999999^{99} also ends with a 9.9. Adding them together yields a number that ends in 8.8.
Thus, D is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.