2000 AMC 8 Problem 12

Attempt Problem 12 of the 2000 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

A block wall 100100 feet long and 77 feet high will be constructed using blocks that are 11 foot high and either 22 feet long or 11 foot long (no blocks may be cut). The vertical joins in the blocks must be staggered as shown, and the wall must be even on the ends. What is the smallest number of blocks needed to build this wall?
344344
347347
350350
353353
356356
Answer: D
Concepts:optimization
Small hint:
Start with all 22-foot blocks
Big hint:
Only every other row needs an extra block to stagger joins
Solution:
The total number of rows in the wall is 7,7, with each row being 11 foot high.
To use the minimum number of bricks, rows 1,1, 3,3, 5,5, and 77 will have the same pattern as the bottom row in the picture, which requires 5050 bricks to construct.
Rows 2,2, 4,4, and 66 will have the same pattern as the upper row in the picture, which has 4949 22-foot bricks in the middle and one 11-foot brick on each end, for a total of 5151 bricks.
When you add up 44 rows of 5050 bricks and 33 rows of 5151 bricks, you get a total of 4⋅50+3⋅51=200+153=3534 \cdot 50 + 3 \cdot 51 = 200 + 153 = 353 bricks.
Thus, D is the correct answer.
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