2000 AMC 8 Problem 10
Attempt Problem 10 of the 2000 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
10.
Ara and Shea were once the same height. Since then Shea has grown while Ara has grown half as many inches as Shea. Shea is now inches tall. How tall, in inches, is Ara now?
Answer: E
Small hint:
Recover the original common height from Shea’s new height
Big hint:
Ara grew half as many inches as Shea
Solution:
Let be Ara and Shea’s initial height. Then we get that
This means that Shea grew inches, which means that Ara grew inches, making her inches tall.
Thus, E is the correct answer.
Problem 10 in other years
- 1985 AMC 8
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