1999 AMC 8 Problem 13

Attempt Problem 13 of the 1999 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

The average age of the 4040 members of a computer science camp is 1717 years. There are 2020 girls, 1515 boys, and 55 adults. If the average age of the girls is 1515 and the average age of the boys is 16,16, what is the average age of the adults?
2626
2727
2828
2929
3030
Answer: C
Concepts:mean
Small hint:
Convert each average into a total age
Big hint:
Subtract the girls’ and boys’ totals from the camp total
Solution:
The sum of the ages of everybody at the camp is 40⋅17=680. 40 \cdot 17 = 680.
The sum of the ages of the girls is 20⋅15=300 20 \cdot 15 = 300 and of the boys is 15⋅16=240. 15 \cdot 16 = 240.
As such, we know that the ages of the adults must be 680−300−240=140. 680 - 300 - 240 = 140.
And therefore, the average age of the adults is then 140÷5=28. 140 \div 5 = 28.
Thus, C is the correct answer.
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