1999 AMC 8 Problem 12

Attempt Problem 12 of the 1999 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

The ratio of the number of games won to the number of games lost (no ties) by the Middle School Middies is 114.\frac{11}{4}. To the nearest whole percent, what percent of its games did the team lose?
24%24\%
27%27\%
36%36\%
45%45\%
73%73\%
Answer: B
Concepts:ratio and proportionpercentage
Small hint:
Use 1111 wins and 44 losses as one batch
Big hint:
The lost fraction is losses over total games
Solution:
The team can be viewed as winning 1111 games and losing 44 games in each batch of 1515 games.
The percent lost is 415⋅100%≈27%\dfrac4{15}\cdot100\%\approx 27\%.
Thus, B is the correct answer.
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