1998 AMC 8 Problem 12

Attempt Problem 12 of the 1998 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1998 AMC 8 solutions, or check the answer key.

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12.

What is the value of the following expression? 2(112)+3(113)+2\left(1-\dfrac{1}{2}\right) + 3\left(1-\dfrac{1}{3}\right) + 4(114)++10(1110) \begin{aligned} &4\left(1-\dfrac{1}{4}\right) + \cdots \\ &\quad {}+ 10\left(1-\dfrac{1}{10}\right) \end{aligned}

4545

4949

5050

5454

5555

Answer: A
Concepts:summationalgebraic manipulation
Difficulty rating: 1090
Solution:

For each integer nn from 22 through 1010,

n(11n)=n1.n\left(1-\frac1n\right)=n-1.

The expression is therefore 1+2++9=451+2+\cdots+9=45.

Thus, the correct answer is A .

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