1997 AMC 8 Problem 13
Attempt Problem 13 of the 1997 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
13.
Three bags of jelly beans contain and beans. The ratios of yellow beans to all beans in each of these bags are and respectively. All three bags of candy are dumped into one bowl. Which of the following is closest to the ratio of yellow jelly beans to all beans in the bowl?
Answer: A
Small hint:
Divide total yellow beans by total beans
Big hint:
Find the number of yellow beans in each bag
Solution:
There are yellow jelly beans in the first bag, yellow jelly beans in the second bag, and yellow jelly beans in the third bag.
The total number of yellow jelly beans is and the total number of jelly beans is The ratio of yellow jelly beans to all the beans is
Thus, A is the correct answer.
Problem 13 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
- 1996 AMC 8
- 1998 AMC 8
- 1999 AMC 8
- 2000 AMC 8
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