1994 AMC 8 Problem 12

Attempt Problem 12 of the 1994 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Each of the three large squares shown is the same size. Segments that intersect the sides of the squares intersect at the midpoints of the sides. How do the shaded areas of these squares compare?
The shaded areas in all three are equal.
Only the shaded areas of II and IIII are equal.
Only the shaded areas of II and IIIIII are equal.
Only the shaded areas of IIII and IIIIII are equal.
The shaded areas of I,I, II,II, and IIIIII are all different.
Answer: A
Concepts:area decompositionarea ratio
Small hint:
Find what fraction of each large square is shaded by cutting each figure into equal smaller pieces.
Big hint:
Divide square II into 88 equal triangles, square IIII into 44 equal cells, and square IIIIII into 1616 equal triangles, then count the shaded pieces in each.
Solution:
In square II,II, 11 of the 44 equal cells is shaded, so 14\tfrac14 of it is shaded.
Square II breaks into 88 equal triangles with 22 shaded, and square IIIIII breaks into 1616 equal triangles with 44 shaded; each of these equals 28=416=14.\tfrac{2}{8} = \tfrac{4}{16} = \tfrac14.
Since every figure has exactly 14\tfrac14 shaded, the shaded areas are all equal.
Thus, the correct answer is A .
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