1993 AMC 8 Problem 6

Attempt Problem 6 of the 1993 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

A can of soup can feed 33 adults or 55 children. If there are 55 cans of soup and 1515 children are fed, then how many adults would the remaining soup feed?
55
66
77
88
1010
Answer: B
Concepts:rate
Small hint:
1515 children need 15÷5=315 \div 5 = 3 cans, so find how many cans remain
Big hint:
Each remaining can feeds 33 adults
Solution:
Feeding 1515 children uses 15÷5=315 \div 5 = 3 cans, leaving 5−3=25 - 3 = 2 cans.
Those 22 cans feed 2×3=62 \times 3 = 6 adults.
Thus, the correct answer is B .
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