1992 AMC 8 Problem 13

Attempt Problem 13 of the 1992 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

Five test scores have a mean (average score) of 90,90, a median (middle score) of 91,91, and a mode (most frequent score) of 94.94. The sum of the two lowest test scores is
170170
171171
176176
177177
not determined by the information given
Answer: B
Concepts:meanmedian (data)mode
Small hint:
The five scores add up to 5×90=450,5 \times 90 = 450, and the middle score is 9191
Big hint:
The mode 9494 must appear at least twice, and both copies must be at or above the median, so the three highest scores are 91,91, 94,94, and 9494
Solution:
The five scores sum to 5×90=450.5 \times 90 = 450. The median is the third score, 91.91. Since 9494 is the mode, it must appear at least twice, and both copies lie above the median, so the two highest scores are 9494 and 94.94.
The three highest scores are 91,91, 94,94, and 94,94, summing to 279.279. So the two lowest sum to 450−279=171.450 - 279 = 171.
Thus, the correct answer is B .
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