1989 AMC 8 Problem 5

Attempt Problem 5 of the 1989 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

What is the value of
−15+9×(6÷3)?-15 + 9 \times (6 \div 3)?
−48-48
−12-12
−3-3
33
1212
Answer: D
Concepts:order of operations
Small hint:
Follow the order of operations: parentheses first, then multiplication, then addition
Big hint:
6÷3=2,6 \div 3 = 2, so the expression becomes −15+9×2-15 + 9 \times 2
Solution:
Inside the parentheses, 6÷3=2.6 \div 3 = 2. Then multiplication comes before addition, so 9×2=18.9 \times 2 = 18.
Finally, −15+18=3.-15 + 18 = 3.
Thus, the correct answer is D .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.