1988 AMC 8 Problem 17
Attempt Problem 17 of the 1988 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
17.
The shaded area is formed by two intersecting perpendicular rectangles, with dimensions as shown. Its area, in square units, is
unable to be determined from the information given
Answer: B
Small hint:
Add the areas of the two rectangles, but the overlapping region gets counted twice
Big hint:
The horizontal rectangle is the vertical one is and the overlap is
Solution:
The horizontal rectangle has area and the vertical rectangle has area Their overlap, a rectangle, has area
Adding the two rectangles counts the overlap twice, so the shaded area is
Thus, the correct answer is B .
Problem 17 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
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