2024 AMC 12B Problem 16

Attempt Problem 16 of the 2024 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

A group of 1616 people will be partitioned into 44 indistinguishable 44-person committees. Each committee will have one chairperson and one secretary. The number of different ways to make these assignments can be written as 3rM,3^r M, where rr and MM are positive integers and MM is not divisible by 3.3. What is r?r?
55
66
77
88
99
Answer: A
Concepts:multiplication principleLegendre’s Formula
Small hint:
The number of assignments is 16!(4!)4 4!⋅124,\dfrac{16!}{(4!)^4\, 4!} \cdot 12^4, where each committee contributes 4⋅3=124 \cdot 3 = 12 chair-and-secretary choices
Big hint:
Track only powers of 3:3: 16!16! gives 36,3^6, the denominator (4!)4 4!(4!)^4\,4! gives 35,3^5, and 12412^4 gives 343^4
Solution:
The number of ways to split 1616 people into 44 indistinguishable groups of 44 is 16!(4!)4 4!.\dfrac{16!}{(4!)^4\, 4!}. Each committee then chooses a chairperson and a secretary in 4⋅3=124 \cdot 3 = 12 ways, contributing 124.12^4. So the total is 16!(4!)4 4!⋅124.\dfrac{16!}{(4!)^4\,4!}\cdot 12^4.
Counting factors of 3:3: 16!16! contributes ⌊163⌋+⌊169⌋=6.\lfloor \frac{16}{3}\rfloor + \lfloor \frac{16}{9}\rfloor = 6. The denominator (4!)4 4!(4!)^4\,4! contributes 4+1=5.4 + 1 = 5. And 124=(22⋅3)412^4 = (2^2\cdot 3)^4 contributes 4.4. Thus r=6−5+4=5.r = 6 - 5 + 4 = 5.
Thus, the correct answer is A.
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