2023 AMC 12B Problem 8

Attempt Problem 8 of the 2023 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

How many nonempty subsets BB of {0,1,2,3,…,12}\{0,1,2,3,\ldots,12\} have the property that the number of elements in BB is equal to the least element of B?B? For example, B={4,6,8,11}B=\{4,6,8,11\} satisfies the condition.
256256
136136
108108
144144
156156
Answer: D
Concepts:combinationscasework
Small hint:
If the least element is m,m, then BB has exactly mm elements, all at least mm
Big hint:
Choose the other m−1m-1 elements from the 12−m12-m integers greater than m:m: this gives (12−mm−1)\binom{12-m}{m-1}
Solution:
If the least element is m (m≥1),m\ (m\ge 1), then ∣B∣=m|B|=m and the remaining m−1m-1 elements come from {m+1,…,12},\{m+1,\ldots,12\}, a set of size 12−m.12-m. The count is ∑m≥1(12−mm−1)=(110)+(101)+(92)+(83)+(74)+(65), \begin{aligned} \sum_{m\ge 1}\binom{12-m}{m-1} &=\binom{11}{0} \\ &\quad {}+\binom{10}{1} \\ &\quad {}+\binom{9}{2} \\ &\quad {}+\binom{8}{3} \\ &\quad {}+\binom{7}{4} \\ &\quad {}+\binom{6}{5}, \end{aligned} which equals 1+10+36+56+35+61+10+36+56+35+6 =144.=144.
Thus, the correct answer is D.
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