2022 AMC 12B Problem 25

Attempt Problem 25 of the 2022 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

Four regular hexagons surround a square with a side length 1,1, each one sharing an edge with the square, as shown in the figure below. The area of the resulting 1212-sided outer nonconvex polygon can be written as mn+p,m\sqrt n + p, where m,m, n,n, and pp are integers and nn is not divisible by the square of any prime. What is m+n+p?m + n + p?
−12-12
−4-4
44
2424
3232
Answer: B
Concepts:regular polygoncoordinate geometryshoelace formula
Small hint:
Each hexagon shares an edge with the square and reaches across to the far side; set up coordinates with the square centered at the origin
Big hint:
The outer boundary has flat edges at distance 3−12\sqrt3 - \tfrac12 and reflex notches where adjacent hexagons’ edges cross, at (52−3, 52−3)\left(\tfrac52 - \sqrt3,\ \tfrac52 - \sqrt3\right)
Solution:
Center the square at the origin with vertices (±12,±12).\left(\pm\tfrac12, \pm\tfrac12\right). Each hexagon shares one edge with the square and extends across to the opposite side; the hexagon on the bottom edge, for instance, has its far (top) edge from (−12,3−12)\left(-\tfrac12, \sqrt3 - \tfrac12\right) to (12,3−12).\left(\tfrac12, \sqrt3 - \tfrac12\right).
The outer boundary is a 1212-gon with flat edges at distance 3−12\sqrt3 - \tfrac12 from the center, convex vertices such as (3−12,12),\left(\sqrt3 - \tfrac12, \tfrac12\right), and four reflex notches where adjacent hexagons’ slanted edges meet, at (52−3,52−3)\left(\tfrac52 - \sqrt3, \tfrac52 - \sqrt3\right) and its symmetric images.
Applying the shoelace formula to these 1212 vertices gives area 163−23,16\sqrt3 - 23, so m=16,m = 16, n=3,n = 3, p=−23,p = -23, and m+n+p=−4.m + n + p = -4.
Thus, the correct answer is B.
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