2022 AMC 12B Problem 25

Attempt Problem 25 of the 2022 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12B solutions, or check the answer key.

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25.

Four regular hexagons surround a square with a side length 1,1, each one sharing an edge with the square, as shown in the figure below. The area of the resulting 1212-sided outer nonconvex polygon can be written as mn+p,m\sqrt n + p, where m,m, n,n, and pp are integers and nn is not divisible by the square of any prime. What is m+n+p?m + n + p?

12-12

4-4

44

2424

3232

Answer: B
Concepts:regular polygoncoordinate geometryshoelace formula
Difficulty rating: 2520
Solution:

Center the square at the origin with vertices (±12,±12).\left(\pm\tfrac12, \pm\tfrac12\right). Each hexagon shares one edge with the square and extends across to the opposite side; the hexagon on the bottom edge, for instance, has its far (top) edge from (12,312)\left(-\tfrac12, \sqrt3 - \tfrac12\right) to (12,312).\left(\tfrac12, \sqrt3 - \tfrac12\right).

The outer boundary is a 1212-gon with flat edges at distance 312\sqrt3 - \tfrac12 from the center, convex vertices such as (312,12),\left(\sqrt3 - \tfrac12, \tfrac12\right), and four reflex notches where adjacent hexagons' slanted edges meet, at (523,523)\left(\tfrac52 - \sqrt3, \tfrac52 - \sqrt3\right) and its symmetric images.

Applying the shoelace formula to these 1212 vertices gives area 16323,16\sqrt3 - 23, so m=16,m = 16, n=3,n = 3, p=23,p = -23, and m+n+p=4.m + n + p = -4.

Thus, the correct answer is B.

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