2021 AMC 12B Fall Problem 12

Attempt Problem 12 of the 2021 AMC 12B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

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12.

For nn a positive integer, let f(n)f(n) be the quotient obtained when the sum of all positive divisors of nn is divided by n.n. For example, f(14)=(1+2+7+14)÷14=127. \begin{aligned} f(14) &= (1 + 2 + 7 + 14) \div 14 \\ &= \dfrac{12}{7}. \end{aligned} What is f(768)−f(384)?f(768) - f(384)?
1768\dfrac{1}{768}
1192\dfrac{1}{192}
11
43\dfrac{4}{3}
83\dfrac{8}{3}
Answer: B
Concepts:sum of factorsprime factorization
Small hint:
Factor 768=28⋅3768 = 2^8 \cdot 3 and 384=27⋅3,384 = 2^7 \cdot 3, then use σ\sigma of a prime power
Big hint:
Put both over a common denominator of 192192
Solution:
Since 768=28⋅3,768 = 2^8 \cdot 3, its divisor sum is (29−1)(1+3)(2^9 - 1)(1 + 3) =511⋅4=2044,= 511 \cdot 4 = 2044, so f(768)=2044768=511192.f(768) = \dfrac{2044}{768} = \dfrac{511}{192}.
Since 384=27⋅3,384 = 2^7 \cdot 3, its divisor sum is (28−1)(1+3)(2^8 - 1)(1 + 3) =255⋅4=1020,= 255 \cdot 4 = 1020, so f(384)=1020384=510192.f(384) = \dfrac{1020}{384} = \dfrac{510}{192}.
The difference is 511−510192=1192.\dfrac{511 - 510}{192} = \dfrac{1}{192}.
Thus, the correct answer is B.
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