2014 AMC 12A Problem 2

Attempt Problem 2 of the 2014 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

At the theater children get in for half price. The price for $5$ adult tickets and $4$ child tickets is $\$24.50.$ How much would $8$ adult tickets and $6$ child tickets cost?

$\$35$

$\$38.50$

$\$40$

$\$42$

$\$42.50$

Answer: B

Concepts:ratio and proportion

Difficulty rating: 1020

Solution:

Since a child ticket is half an adult ticket, $5$ adult and $4$ child tickets equal $5+\tfrac12\cdot4=7$ adult tickets, so one adult ticket costs $\dfrac{24.50}{7}=\$3.50.$

The second purchase equals $8+\tfrac12\cdot6=11$ adult tickets, costing $11\cdot 3.50=\$38.50.$

Thus, the correct answer is B.

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