2014 AMC 12A Problem 25

Attempt Problem 25 of the 2014 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12A solutions, or check the answer key.

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25.

The parabola PP has focus (0,0)(0,0) and goes through the points (4,3)(4,3) and (4,3).(-4,-3). For how many points (x,y)P(x,y)\in P with integer coordinates is it true that 4x+3y1000?|4x+3y|\le1000?

3838

4040

4242

4444

4646

Answer: B
Concepts:parabolalattice pointDiophantine Equation
Difficulty rating: 2650
Solution:

Since (0,0)(0,0) is the midpoint of A=(4,3)A=(4,3) and B=(4,3),B=(-4,-3), the segment ABAB is the latus rectum, so the directrix is parallel to ABAB at distance 55 on the far side, namely 4y3x+25=0.4y-3x+25=0.

Equating distances to focus and directrix gives (4x+3y)2(4x+3y)^2 =25(25+2(4y3x)).=25\big(25+2(4y-3x)\big). Writing 4x+3y=5s4x+3y=5s forces 5s,5\mid s, and s=5ts=5t forces tt odd; with t=2u+1t=2u+1 the integer points are x=6u2+2u+4,y=8u2+14u+3. \begin{aligned} x&=-6u^2+2u+4,\\ y&=8u^2+14u+3. \end{aligned}

Then 4x+3y=50u+251000|4x+3y|=|50u+25|\le1000 iff 2u+139,|2u+1|\le39, i.e. 20u19.-20\le u\le19. That gives 4040 lattice points.

Thus, the correct answer is B.

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