2014 AMC 12A Problem 17

Attempt Problem 17 of the 2014 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12A solutions, or check the answer key.

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17.

A 4×4×h4\times4\times h rectangular box contains a sphere of radius 22 and eight smaller spheres of radius 1.1. The smaller spheres are each tangent to three sides of the box, and the larger sphere is tangent to each of the smaller spheres. What is h?h?

2+272+2\sqrt7

3+253+2\sqrt5

4+274+2\sqrt7

454\sqrt5

474\sqrt7

Answer: A
Concepts:3D geometryspherePythagorean Theorem
Difficulty rating: 1800
Solution:

Place the box with a corner at the origin. Each small sphere sits in a corner with center 11 unit from three faces. The four top small-sphere centers form a square of side 2,2, whose center lies on the box axis; a corner of that square is 2\sqrt2 from the center.

The big sphere's center is on the axis, at distance 2+1=32+1=3 from each top small center. The vertical gap between them is 3222=7.\sqrt{3^2-\sqrt2^2}=\sqrt7.

The big center is at height h2\dfrac h2 and the top small centers at height h1,h-1, so (h1)h2=7,(h-1)-\dfrac h2=\sqrt7, giving h2=1+7\dfrac h2=1+\sqrt7 and h=2+27.h=2+2\sqrt7.

Thus, the correct answer is A.

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