2013 AMC 12B Problem 16

Attempt Problem 16 of the 2013 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 12B solutions, or check the answer key.

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16.

Let ABCDEABCDE be an equiangular convex pentagon of perimeter 1.1. The pairwise intersections of the lines that extend the sides of the pentagon determine a five-pointed star polygon. Let ss be the perimeter of this star. What is the difference between the maximum and the minimum possible values of s?s?

00

12\dfrac{1}{2}

512\dfrac{\sqrt5 - 1}{2}

5+12\dfrac{\sqrt5 + 1}{2}

5\sqrt5

Answer: A
Concepts:equiangular polygonisosceles triangleinvariant
Difficulty rating: 1890
Solution:

An equiangular pentagon has all interior angles 108,108^\circ, so each point of the star is an isosceles triangle with base angles 7272^\circ and apex 36.36^\circ. By the equal base angles, each point contributes two sides that are the same fixed multiple cc of the pentagon side it rests on. Summing over the five points, the star perimeter equals 2c(pentagon perimeter)=2c,2c\cdot(\text{pentagon perimeter}) = 2c, independent of the individual side lengths. So ss is constant, and the difference between its maximum and minimum values is 0.0. Thus, the correct answer is A.

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