2009 AMC 12A Problem 16

Attempt Problem 16 of the 2009 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

A circle with center CC is tangent to the positive xx- and yy-axes and externally tangent to the circle centered at (3,0)(3, 0) with radius 1.1. What is the sum of all possible radii of the circle with center C?C?
33
44
66
88
99
Answer: D
Concepts:tangent circlescoordinate geometryVieta’s Formulas
Small hint:
A circle tangent to both positive axes with radius rr has center (r,r)(r, r)
Big hint:
External tangency gives distance r+1r + 1 between (r,r)(r, r) and (3,0);(3, 0); form a quadratic in rr and use Vieta
Solution:
A circle tangent to both positive axes with radius rr has center (r,r).(r, r). External tangency to the circle at (3,0)(3, 0) of radius 11 means the distance between centers is r+1r + 1: (r−3)2+r2=(r+1)2.(r - 3)^2 + r^2 = (r + 1)^2.
Expanding gives r2−8r+8=0.r^2 - 8r + 8 = 0. Both roots r=4±22r = 4 \pm 2\sqrt{2} are positive, and by Vieta’s formulas their sum is 8.8.
Thus, the correct answer is D.
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